7^2x-3=(1/49)^x+1

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Solution for 7^2x-3=(1/49)^x+1 equation: 



7^2x-3=(1/49)^x+1

We move all terms to the left:

7^2x-3-((1/49)^x+1)=0



Domain of the equation: 49)^x+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7^2x-((+1/49)^x+1)-3=0

We multiply all the terms by the denominator


7^2x*49)^x+1)-((-3*49)^x+1)+1=0

We add all the numbers together, and all the variables

7^2x*49)^x+1)-((-147)^x+1)+1=0

Wy multiply elements

343x^3-147)^x+1)+1=0

We do not support expression: x^3

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